tan2θ·tanθ = 1 হলে θ = ?

ব্যাখ্যা

tan2θ·tanθ = 1 ⇒ {2tanθ/(1 − tan²θ)}·tanθ = 1 ⇒ 3tan²θ = 1 ⇒ tanθ = 1/√3 = tan(π/6) ∴ θ = nπ + π/6 (সাধারণভাবে θ = nπ ± π/6)