∫₃² x/(x² + 1) dx এর মান কত?

ব্যাখ্যা

∫₃² x/(x² + 1) dx = (1/2)∫₃² 2x/(x² + 1) dx = (1/2)[ln(x² + 1)]₃² = (1/2)(ln5 − ln10) = (1/2)ln(1/2) = −(1/2)ln2